Security
How do I generate random string?
package org.kodejava.security; import java.security.SecureRandom; import java.util.Random; public class RandomString { public static final String SOURCES = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890"; public static void main(String[] args) { RandomString rs = new RandomString(); System.out.println(rs.generateString(new Random(), SOURCES, 10)); System.out.println(rs.generateString(new Random(), SOURCES, 10)); System.out.println(rs.generateString(new Secure...
Artikel oleh Wayan · Sumber: Kode Java ↗
Terjemahan artikel ini belum tersedia. Isi asli ditampilkan.
package org.kodejava.security;
import java.security.SecureRandom;
import java.util.Random;
public class RandomString {
public static final String SOURCES =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890";
public static void main(String[] args) {
RandomString rs = new RandomString();
System.out.println(rs.generateString(new Random(), SOURCES, 10));
System.out.println(rs.generateString(new Random(), SOURCES, 10));
System.out.println(rs.generateString(new SecureRandom(), SOURCES, 15));
System.out.println(rs.generateString(new SecureRandom(), SOURCES, 15));
}
/**
* Generate a random string.
*
* @param random the random number generator.
* @param characters the characters for generating string.
* @param length the length of the generated string.
*/
public String generateString(Random random, String characters, int length) {
char[] text = new char[length];
for (int i = 0; i < length; i++) {
text[i] = characters.charAt(random.nextInt(characters.length()));
}
return new String(text);
}
}
Example string produced by the code snippets are:
bJGjSgoy7G
SoeTjBy83s
IolJZtkttJixAVY
ZOvQnICNcwcCdJ8
